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Paul [167]
3 years ago
7

A student is given data that follows a normal distribution. According to the data, the mean amount of time that students spent r

eading outside of school each month was 10 hours, and the standard deviation was 2 hours. The student creates a normal distribution curve to model the situation and labels the curve so that 34% of the students fall in the range between 10 and 12 hours. Select the information that justifies the student's labeling.
a. Only 68% of the students will fall in the range of 10- 2 and 10 + 2 hours.
b. Only 95% of the students will fall in the range of 10-2 and 10+2 hours
c. Only 68% of the students will fall in the range of 10-6 and 10+6 hours
d. Only 95%of the students will fall in the range of 10 -8 and 10 + 8 hours.
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

a. Only 68% of the students will fall in the range of 10- 2 and 10 + 2 hours.

Step-by-step explanation:

He appies the empirical 68-95-99.7 rule, where 68% of the data is expected to be within ne standard deviation from the mean, to the right and to the left.

Half of this (68%/2=34%) will be between the mean and one deviation standard to the right. This is between 10 hours and 10+2=12 hours.

The right answer is:

a. Only 68% of the students will fall in the range of 10- 2 and 10 + 2 hours.

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Membership at a local gym increased from 500 members to 800 members in one year. What was the percent of increase?
Tomtit [17]

Answer: 60%

Step-by-step explanation:

(300/500)*100

3 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
What is the equivalent of 2/7​
Rudik [331]

Answer:

4/14 is equivalent to 2/7

Step-by-step explanation:

mark me as brainliest ❤️

7 0
3 years ago
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a tiger can eat food that weighs up to about 15% of it's body weight if a tiger can eat 75 lbs of food how much does a tiger wei
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So you want to take the amount of food (75lbs), divide it by the amount of the tiger's food weight (15%) and then multiply it by it's total body weight (100%)
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Where is the picture
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