All categories

3 years ago

There are 1,760 yards in a mile. How many full laps would Danny have to run around the block to run a mile?

Mathematics

1 answer:

Dvinal [7]3 years ago

5 0

2 my brotha boi only 5,560 or so feet and more than that so its certainly 2 laps.

You might be interested in

What is the measure of

Kamila [148]

Answer:

64.4

Step-by-step explanation:

In one of the trig formulas, it states sin <a/A = sin<b/B = sin<c/C

So we have in this case:

sin(70)/12 = sin x/14 Note: x is just a variable for the angle <ABC

14(sin70)/12 = sin x

sin^-1(14(sin70)/12) = x

x=64.4

Your welcome, and comment if you have any questions! :D

6 0

3 years ago

Karyn proofread a 15 pages in 2 hours for $40.

xxMikexx [17]

A. 8 pages per hour because 120 (2 hours) ÷15=8
b. $40÷15 (pages)=$2.70 (rounded)

3 0

4 years ago

Which equation represents the situation below if "c" represents the number of chocolate chip cookies?Heather baked 200 cookies o

lisov135 [29]

Answer:

200 - 65 = c

Step-by-step explanation:

You would need to subtract the 65 oatmeal cookies that Heather has from the 200 in total. You would then get how many chocolate chip cookies that Heather would have left. Hope this helped.

4 0

3 years ago

A certain microprocessor requires either 2, 3, 4, 8, or 12 machine cycles to perform various operations. Twenty-five percent of

myrzilka [38]

Answer:

The average number of machine cycles per instruction for this microprocessor is 5.8.

Step-by-step explanation:

To find the average number of machine cycles per instruction for this microprocessor, we multiply each number of cycles for it's relative frequency.

We have that:

25% require 2 cycles.

20% require 3 cycles.

17.5% require 4 cycles.

12.5% require 8 cycles.

25% require 12 cycles.

So the average number is:

$M = 0.25*2 + 0.2*3 + 0.175*4 + 0.125*8 + 0.25*12 = 5.8$

3 0

3 years ago

Rewrite log[(ac^3/b)]using the properties of logarithms

stellarik [79]

Answer:

1st option

Step-by-step explanation:

$log( \frac{a {c}^{3} }{b} ) \\ = log(a {c}^{3}) - logb \\ = loga + log{c}^{3} - logb \\ = loga + 3logc - logb$

note that the cube is only for c not a

6 0

3 years ago