2(4 + 2x) ≥ 5x + 5
First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4.

Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself.

Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.

Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3.

Fifth, we can switch sides now to get the result of this problem.

Answer:
Answer:
(x, y) = (6, 1) is the solution
Step-by-step explanation:
Each of the equations is written in "slope-intercept" form:
y = mx + b . . . . . . . . where m is the slope and b is the y-intercept
<u>First equation</u>
The y-intercept is +7 and the slope is -1. That means the line goes down 1 unit for each unit it goes to the right. It will go through the points (0, 7) and (7, 0).
<u>Second equation</u>
The y-intercept is -2 and the slope is 1/2. That means the line goes up 1 unit for each 2 units it goes to the right. It will go through the points (0, -2) and (4, 0).
The lines will intersect at the point (6, 1), which is the solution found by graphing.
a fraction that has a denominator of a power of 10
Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.