All categories

2 years ago

Use equivalent ratios to find unknown value plz halp!!!!

Mathematics

2 answers:

iogann1982 [59]2 years ago

7 0

Answer:

Step-by-step explanation:

It might be 21/30 , hope it helps though :)

GrogVix [38]2 years ago

7 0

Answer:

21 is the un known value.

Step-by-step explanation:

10 times 3=30

7 times 3 = 21

so 21/30 is your answer.

You might be interested in

A neighbor told Bob that he should apply a protective “sealant” to the driveway. Bob found a product at the home improvement sto

Rufina [12.5K]

Answer:

37.99 doller

Step-by-step explanation:

trust me

7 0

1 year ago

there are 27 children in Ms. kloot's class. when the flu was going around , about 26% of the students in the class were absent.

ValentinkaMS [17]

Answer:

About 8 children were sick

Step-by-step explanation:

The total number of children in Ms. kloot's class is 27.

The percentage of students who were absent due to the flu 26.

Number of children who were sick

$= \frac{26}{100} \times 27$

This simplifies to:

$= 7.02$

Therefore about 8 children were sick

8 0

2 years ago

Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug

gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems

In C(5,3)=10ways, this can be achieved

In part a:

Space sample chooses 3 of a 5 systems

$(M_1, \ M_2,\ M_3),$ $(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),$ $(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}$

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort

Outcomes probable =

$(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6$

$\to p(A)=\frac{6}{10}\\\\$

$=0.6$

In point c:

B = highest effort that is $M_5$

Potential result=

$(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6 \\\\$

$\to B= \frac{6}{10} \\\\$

$=0.6$

$\to P(B)=10$

In point d:

$\to \ A \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)$

$\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \$

$=0.3$

In point e:

$\to (A \cup B) = (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9$ $\to P(A \cap B)=\frac{9}{10}$