Answer:
d. It is assumed that the search pool is ordered.
Explanation:
A binary search/logarithimic search/half interval search/binary chop refers to search algorithm in computer science that sorts data in array in key:value arrangements. In order to locate a value in binary search, the key to the value in a sorted array is located. A binary search is characterized by an ascending, descending order arrangement of the array.
Answer:
The correct answer to the following question will be "Mechanical off mode".
Explanation:
- The device will appear to be either on or off to the user. No other states are measurable. The device does, however, support various power states that suit the power states specified in the ACPI specification. Such states also differ, like hybrid sleep and rapid startup. This subject discusses certain states and how they will be represented.
- The system is completely off, and no power is used. Only after a full reboot will the machine return to working condition.
- It is called mechanical off mode when the machine and all parts, except for the actual-time clock, are down powered.
Therefore, Mechanical off mode is the right answer.
The second generation of home consoles occurred from (1976-1988) at this time the most popular and consoled regarded as best was the Atari 2600
Answer:
The method in Java is as follows:
public static int numUnique(int list[]) {
int unique = 1;
for (int i = 1; i < list.length; i++) {
int j = 0;
for (j = 0; j < i; j++) {
if (list[i] == list[j])
break;
}
if (i == j)
unique++;
}
return unique;
}
Explanation:
This line defines the numUnique method
public static int numUnique(int list[]) {
This initializes the number of unique elements to 1
int unique = 1;
This iterates through the list
for (int i = 1; i < list.length; i++) {
The following iteration checks for unique items
int j = 0;
<em> for (j = 0; j < i; j++) {
</em>
<em> if (list[i] == list[j]) </em><em>If current element is unique, break the iteration</em><em>
</em>
<em> break; </em>
<em> }
</em>
if (i == j)
unique++;
}
This returns the number of unique items in the list
return unique;
}