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2 years ago

What is 8 and 4/25 as an improper fraction

Mathematics

1 answer:

tresset_1 [31]2 years ago

5 0

Answer:

The answer would be 204/25

Step-by-step explanation:

25 x 8 = 200

200 + 4 = 204

Thus, you get:

204/25

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2/3 - 4/9x + 1 = 2 7/9 By the way, those are fractions and mixed numbers Solve x

sukhopar [10]

X=-5/2

that’s if you’re saying 2 & 7/9

8 0

3 years ago

Read 2 more answers

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago

Can someone explain to me how I am supposed to do this please?

balandron [24]

I think Sam is correct cuz SQ is a bigger rectangle and for OM it is smaller and we only know the width

8 0

3 years ago

A positive integer is 47 more than 9 times another. Their product is 1860. Find the two integers.

svlad2 [7]

X = 47 + 9y
xy = 1860

y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0

> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12

12y = 1860
y = 155

integers are 12 and 155

8 0

3 years ago

What is the solution of the system? Use elimination. 3 (-5x-2y=6) 3x+6y=6

Iteru [2.4K]

Answer:

x = -2 and y = 2

Step-by-step explanation:

The given equations are :

-5x-2y=6 ...(1)

3x+6y=6 ...(2)

Multiply equation (1) by 3. SO,

-15x-6y=18 ...(3)

Adding equation (2) and (3).

3x+6y-15x-6y = 6+18

-12x = 24

x = -2

Put the value of x in equation (1).

-5(-2)-2y=6

10-2y=6

4=2y

y = 2

So, the value of x is -2 and y is 2.

6 0

2 years ago