Answer:
![h=\frac{1}{2}x](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B1%7D%7B2%7Dx)
Step-by-step explanation:
The volume of the mentioned object is
![V=B \times h](https://tex.z-dn.net/?f=V%3DB%20%5Ctimes%20h)
Where
is the base area, which is defined
, because the base is a square which side is
units long.
Additionally, we know that the volume of the object is
![V=\frac{1}{2}x^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B2%7Dx%5E%7B3%7D)
Replacing the first expression and the volume of the base, we have
![x^{2} \times h=\frac{1}{2}x^{3}\\ h=\frac{1}{2}x](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%5Ctimes%20h%3D%5Cfrac%7B1%7D%7B2%7Dx%5E%7B3%7D%5C%5C%20%20h%3D%5Cfrac%7B1%7D%7B2%7Dx)
Therefore, the expression that represents the height of the volume is
![h=\frac{1}{2}x](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B1%7D%7B2%7Dx)
ANSWER IS A I THINK.. hOPE I HELPED! :)
Answer:
35 minutes
Step-by-step explanation:
2 hrs 4 min= 160 min
3 hrs 15 min= 195 min
195-160=35
Answer:
Answer choice C
Step-by-step explanation:
The arc cosine of -0.65 is about 2.278 radians, which rounds to 2.28 or answer choice C. Hope this helps!
No solution . This problem makes no sense .