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nlexa [21]
4 years ago
11

Please answer me this equation

Mathematics
1 answer:
dedylja [7]4 years ago
8 0
Hello,

Perimeter is a function of the number of hexagons.

p_1=6\\
p_2=2*6-1\\
p_3=3*6-2\\
p_4=4*6-3\\\\

\boxed{p_n=n*6-(n-1)}\ =6n-n+1=\boxed{5n+1}\\



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The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima
drek231 [11]
Hello,
\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\



x=-1.81053571 and y=<span> 5,27803957 </span>

Download xls
3 0
3 years ago
Read 2 more answers
As your sample size grows larger, the n - 1 adjustment for the standard deviation has a:______
kumpel [21]

As your sample size grows larger, the n - 1 adjustment for the standard deviation has a smaller impact on the estimates of standard deviation.

<u>Step-by-step explanation:</u>

The average (mean) of sample's distribution seems to be the same as the distribution mean at which samples were taken. The means of mean distribution will not change. However, the standard deviations for the samples mean is the standard deviations of the primary distribution divided by square roots of the samples size.

The standard deviations of means decreases as the samples size increases. Likewise, when the samples size decreases, the standard deviations for the samples mean increases. So, there is a little impact on standard deviations estimation when sample size increases.

8 0
3 years ago
3x+8y=15<br> 2x−8y=10<br> Solve for x
exis [7]
X=5 Y=0 hope this helps
6 0
2 years ago
Which direction does the graph of f(x) = (x − 3)(2x − 5) open?
Mamont248 [21]
Up

X= 1,2,11/4,4,5
Y=6,1,-1/8,3,10
5 0
3 years ago
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What is the x-intercept (-5,-5) (10,-2)
Andre45 [30]

Answer:

(20,0)

Step-by-step explanation:

slope = (y2 - y1) / (x2 - x1)

(-5,-5).....x1 = -5 and y1 = -5

(10,-2)...x2 = 10 and y2 = -2

slope = (-2 - (-5) / (10- (-5) = (-2 + 5) / (10 + 5) = 3/15 = 1/5

y = mx + b

slope(m) = 1/5

use either point, I will use (10,-2)...x = 10 and y = -2

now we sub

-2 = 1/5(10) + b

-2 = 2 + b

-2 - 2 = b

-4 = b

so the equation for this line is : y = 1/5x - 4

to find the x intercept, sub in 0 for y and solve for x

y = 1/5x - 4

0 = 1/5x - 4

-1/5x = -4

x = -4 * -5

x = 20.......so ur x intercept is (20,0) <====

6 0
3 years ago
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