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zhuklara [117]
3 years ago
14

X+ =4+2y=5 solve this​

Mathematics
2 answers:
Fiesta28 [93]3 years ago
3 0

x+4+2y=5

 -4        -4

x+2y=1

-x      -x

2y=-x+1

/2   /2  /2

y=x/2+1/2

---

hope it helps

yKpoI14uk [10]3 years ago
3 0

Use ma   t h  way it helps with these types of equations

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A question on my test:
Andre45 [30]

Answer:

180degrees

Step-by-step explanation:

Given the expression cos^2x - cos x - 2 = 0

Let P = cos x

P^2 - P - 2 = 0

Factorize

P^2 - 2P + P - 2 =0

P(P-2)+1(P-2) = 0

P-2 = 0 and P + 1 = 0

P = 2 and P = -1

Since P = cos x

cos x = -1

x = arccos(-1)

x = 180degrees

Hence the require angle is 180degrees

8 0
3 years ago
How would i find the square root of this problem? <img src="https://tex.z-dn.net/?f=-%20%5Csqrt%7B%5Cfrac%7B25%7D%7B36%7D%20%7D%
NARA [144]
- \sqrt{\frac{25}{36} } =-\frac{5}{6}
6 0
3 years ago
Find the 53rd term of the arithmetic sequence -12, -1, 10
RSB [31]

440 is the answer

Tn=a+(n-1)d

Tn=53

a= -12

n=53

d= 11

-12+(53-1)11 = 440

5 0
3 years ago
Read 2 more answers
Math question plz give answer with explanation will report if it is a non-sense answer. I just want to make sure I am doing it r
vladimir1956 [14]
Answer:
JKL

Working out:
N/A

Note:
It is not DEF because that’s the answer when it rotates clockwise. The question is asking for when the rotation is counterclockwise.
I hope this helps :)
6 0
3 years ago
The vertical height v, in feet, of a snowboarder jumping off of an overhang can be modeled by the function h(t)=15-10t-16t^2, wh
olga55 [171]
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...

Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start. 

h(t)= 15 +10t - 16t^2

In order to use the QF or factoring I will need to make h(t)=0. Simply done by:

0= 15 +10t -16t^2

Looking at the numbers, I'd prefer to use the QF so here it is:

x= \frac{-b + or -  \sqrt{b^{2}-4ac } }{2a}

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

x= \frac{-b -\sqrt{b^{2}-4ac } }{2a}

And I know that a= -16, b= 10, and c=15. So all that's left to do is substitute and solve.

x= \frac{-10 -\sqrt{-16^{2}-4*-16*15 } }{2*-16} 

There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.

Exact answer: \frac{5-4 \sqrt{15} }{8} or rounded answer: ≈1.31 seconds.

Hope this helps!
NoThisIsPatrick

7 0
3 years ago
Read 2 more answers
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