True, hope this helps you.
Answer:
are zeroes of given quadratic equation.
Step-by-step explanation:
We have been a quadratic equation:
![2x^2-10x-3](https://tex.z-dn.net/?f=2x%5E2-10x-3)
We need to find the zeroes of quadratic equation
We have a formula to find zeroes of a quadratic equation:
![x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bb%5E2%5Cpm%5Csqrt%7BD%7D%7D%7B2a%7D%5Ctext%7Bwhere%7DD%3D%5Csqrt%7Bb%5E2-4ac%7D)
General form of quadratic equation is ![ax^2+bx+c](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc)
On comparing general equation with b given equation we get
a=2,b=-10,c=-3
On substituting the values in formula we get
![D=\sqrt{(-10)^2-4(2)(-3)}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28-10%29%5E2-4%282%29%28-3%29%7D)
![\Rightarrow D=\sqrt{100+24}=\sqrt{124}](https://tex.z-dn.net/?f=%5CRightarrow%20D%3D%5Csqrt%7B100%2B24%7D%3D%5Csqrt%7B124%7D)
Now substituting D in
we get
![x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%28-10%29%5E2%5Cpm%5Csqrt%7B124%7D%7D%7B2%5Ccdot%202%7D)
![x=\frac{100\pm\sqrt{124}}{4}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B100%5Cpm%5Csqrt%7B124%7D%7D%7B4%7D)
![x=\frac{100\pm2\sqrt{31}}{4}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B100%5Cpm2%5Csqrt%7B31%7D%7D%7B4%7D)
![x=\frac{50\pm\sqrt{31}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B50%5Cpm%5Csqrt%7B31%7D%7D%7B2%7D)
Therefore, ![x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B50%2B%5Csqrt%7B31%7D%7D%7B2%7D%2C%5Cfrac%7B50-%5Csqrt%7B31%7D%7D%7B2%7D)
B
First you have to change 2 1/2 into 5/2
To multiply fractions use the method
Keep Change Flip
5/2 x 3/1 =15/2
Which simplifies to 7 1/2
Answer:
Hello, Friend! ^^
The Answer Is 13 Inches <3
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Hope this helps! ^^ :3