Answer:
the answer is the 3rd option!
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
The expression for the total cost of their trip is 7 + 2x + 3y.
As per the question, assuming the number of bottles to be x and number of bags to be y. The equation will have one time fee of admission, product of cost of bottles and number of bottles and product of cost of bags and number of chips bags.
The one time fee and two products will be added to form the expression. Forming the equation now -
Expression = 7 + 2x + 3y
Therefore, the expression of trip when x bottles of water were bought during the visit is 7 + 2x + 3y.
Learn more about expression -
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Answer:
Mary's mistake was that she didn't take into account of the power that 10 is raised to; since 2.01 is multiplied by 10 to the 6, it makes 2.01 bigger. You can also expand the number to check:
2 010 000 vs. 4800
