All categories

3 years ago

Solve for b in: (2B/x)-Q=Z

Mathematics

2 answers:

andrezito [222]3 years ago

7 0

Answer:

B = (zx/2)+ (qx/2)

Step-by-step explanation:

Montano1993 [528]3 years ago

7 0

Answer:

b = x(z+q)/2

Step-by-step explanation:

step 1: add Q to each side

step 2: multiply each side by x

step 3: divide each side by 2

You might be interested in

Pls help me, i dont know what i’m doing

Keith_Richards [23]

Answer:

The answer is in the pic above

7 0

2 years ago

Will give brainiest!!! It is scattered plots and predictions and on the questions that have writing on them tell me whether it i

Oxana [17]

Answer:uno

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI

Vadim26 [7]

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

$P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}$

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

4 0

2 years ago

If x = -3 calculate the value of 2xsquared+x

pochemuha

33. 2x-3= -6
-6^2(squared) = 36
36 +(-3) = 33

5 0

2 years ago

Read 2 more answers