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soldi70 [24.7K]
3 years ago
10

The probability of randomly drawing a red card from a bag that contains red, blue, and green cards is 3/10. What is the probabil

ity of not drawing a red card?
Mathematics
1 answer:
Katarina [22]3 years ago
7 0
If the probability of drawing a red card is 3/10, then if we take this fom a whole, 10/10, we can find the probability of not choosing a red card.
10/10-3/10=7/10

The probability of not drawing a red card is 7/10 or 70%.
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If an if then statement and its converse are identical, then which shows the form of the statement?
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Answer:

If both statements are true or if both statements are false then the converse is true​. A conditional and its converse do not mean the same thing.

Step-by-step explanation:

3 0
3 years ago
(0,5, 1, 17)<br> What is the number of subsets <br><br> What is the number of proper subsets
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16

Step-by-step explanation:

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7 0
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EASY 5TH GRADE QUESTION. WILL GIVE BRAINLIEST <br><br> How would you read the number -30?
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4 0
2 years ago
g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control
Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that p = \frac{1}{33}

A local hospital randomly selects five births.

This means that n = 5

What is the probability that at least one of the births results in a defect?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426

0.1426 = 14.26% probability that at least one of the births results in a defect.

4 0
3 years ago
Pls help ill give credits and please NO LINKS
Romashka [77]
If you say “no links” they’ll most likely give you a link


anyways the answer is 25%
4 0
3 years ago
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