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Bad White [126]
2 years ago
15

Please help with this TWO ANSWERS required

Mathematics
1 answer:
lawyer [7]2 years ago
3 0

Answer:

a) The equation of V and W

         V = k W

b) The value of  V = 666.6

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that V is inversely proportional to W

                       V∝ W

               ⇒      V = k W

              ⇒      40 = k (0.9)

              ⇒     k = \frac{40}{0.9} = 44.44

<u><em>Step(ii):-</em></u>

Given that W = 15  and k = 44.44

we have to find the value is 'V'

                       V = k W

            ⇒       V = 44.44 × 15

           ⇒        V = 666.6

           

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Answer:

{8}^{x}  \times  {16}^{x }  - 1 = 1 \\  {2}^{3x}  \times  {2}^{4x}  = 1 + 1 \\  {2}^{7x}  =  {2}^{1}  \\ 7x = 1 \\ x =  \frac{1}{7}

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3 years ago
Which of the following is a characteristic of the repeating shapes in a tessellation?A. Shapes cannot be regular polygons.B. Sha
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What is the length of BC , rounded to the nearest tenth?
Arte-miy333 [17]

Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

we have

AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

AB^{2}=169

AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

AC=(13*13)/5=33.8\ units

Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

8 0
3 years ago
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Fittoniya [83]

Answer:

7y

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6 0
3 years ago
6
8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16     Eqn 1

8x+5y=113    Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

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Subtracting Eqn 3 from Eqn 2

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8x+5y-5x-5y=33

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Dividing both sides by 3

\frac{3x}{3}=\frac{33}{3}\\x=11

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0
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