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attashe74 [19]
3 years ago
14

Solve for x (8x-4), (3x+17), (17x-23)

Mathematics
2 answers:
swat323 years ago
7 0
That’s your answer i think

Strike441 [17]3 years ago
3 0

Answer:

=408x3+1556x2−4008x+1564

Step-by-step explanation:\

(8x−4)(3x+17)(17x−23)

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Whats the next number 0 3 8 15 24 35
exis [7]
I believe it is 48. 
0+3=3
3+5=8
8+7=15
15+9=24
24+11=35
35+13=48
5 0
3 years ago
Item 3 What is the length of the base of a right triangle with an area of 15 m² and a height of 3 m? 5 m 10 m 30 m 45 m
Ksivusya [100]

Answer:

10m

Step-by-step explanation:

Use the area of triangle:

Area of triangle =

\frac{1}{2}   \times base \:  \times height

1/2 × b × 3 = 15

b × 3 = 30

b = 30/3

b = 10

3 0
3 years ago
If theta=3pi/4<br><br> Sin theta=?<br> Cos theta=?
Snowcat [4.5K]

Answer:

For ease of writing, θ =x

sin(x)=\frac{1}{\sqrt{2} }

cos(x)=-\frac{1}{\sqrt{2} }

Step-by-step explanation:

Our angle is x=\frac{3\pi }{4}

To find our answers for sin(\frac{3\pi}{4} ) and cos(\frac{3\pi}{4} ), we will need to use a unit circle. (I have attached the image of one).

Recall that the sin of an angle is equal to the y-value of the corresponding ordered pair.

And the cos of an angle is equal to the x-value of the corresponding ordered pair.

For the angle x=\frac{3\pi }{4}, the ordered pair is (-\frac{1}{\sqrt{2}} }, \frac{1}{\sqrt{2} } )

This means that

sin(x)=\frac{1}{\sqrt{2} }

cos(x)=-\frac{1}{\sqrt{2} }

7 0
3 years ago
Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The
andrew11 [14]
The system can be explained in equation form as x - y =4, an (x + y)/2 = 18. Based on these equations, we can plus in numbers from the given answers and come up with a solution where both equations are satisfied. The two numbers that satisfy both equations are (20, 16).
5 0
3 years ago
Use the graph below to answer the following question: List the integer value(s) of x in the open interval from –2 to 5 where the
DedPeter [7]
To start off, the wording of this question is pretty technical. Let's reword the question to make it a bit easier to understand.

From the open interval from -2 to 5 (meaning between but not including those integers), list every integer for x at which x approaches a defined y point on the curve, regardless of whether it actually takes that y value at that point. 

Let's start with the first eligible integer, -1. 
The limit, from both sides, as x approaches -1 is y=-1. 
However, y = -2 at this point. 

At 0, x continuous and defined on the curve where you would expect it, and therefore the limit at x=0 is its y value at that point, 0.

x=1 is not eligible, because its left-side limit (when approaching from the left) and right-side limit (when approaching from the right), are distinct. 

x=2 has a clear defined limit. It is continuous and defined at that point. The limit looks to be around y= 1.8

x=3 does not feature a clearly defined, finite value, since the limit at x=3 is
-∞

x=4, like x=0 and x=2, has a clear and finite limit, since it is continuous at that point.

Answers are x=-1, x=0, x=2, and x=4
or
{-1, 0, 2, 4}
6 0
3 years ago
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