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2 years ago

What is the first step to isolate the variable term on one side of the equation?

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

4 0

Answer:

The basic technique to isolate a variable is to “do something to both sides” of the equation, such as add, subtract, multiply, or divide both sides of the equation by the same number. By repeating this process, we can get the variable isolated on one side of the equation.

Step-by-step explanation:

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Which of these numbers is prime?<br> 25, 26, 35, 39, 43

ELEN [110]

Answer:

The only number prime is 43

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more

Llana [10]

Given :

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.

To Find :

How many tickets were sold to students.

Solution :

Ticket sold to teachers, T = 563 .

Ticket sold to parents, P = 904 .

Let, ticket sold to students are S.

Now, it is given that :

S = T + 904

S = 563 + 904

S = 1467 students

Therefore, tickets sold to students are 1467 .

Hence, this is the required solution.

6 0

2 years ago

PLEASE ANSWER QUICK!!

Citrus2011 [14]

Answer:

A) B is greater

B) when C = 21, A = 5 and B = 15

C) A must be 0, 5, or 12 for C to be greater than B

Step-by-step explanation:

A) when a = -3, c = -20 and b = 4(-3)-5 so B = -17

B) when c = 21, a = 5 and b = 4(5)-5 so B = 15

C) C is greater than B when a = 0, 5, and 12

when a = 0, b = 4(0)-5 or -5

when a = 5, b = 4(5)-5 or 15

when a = 12, b = 4(12)-5 or 43

3 0

2 years ago

A frog leaps 24 inches. The highest point in the jump is 6 inches. Assume the frog starts at (0,0). What quadratic function mode

Ivanshal [37]

The path is in the shape of a parabola, the horizontal length is 24, so the middle point is at x=12, the symmetry line is x=12, the highest point (the vertex) is at (12,6)
the equation in vertex form is y=a(x-12)²+6
next, find a by using either one of the two points, the starting point (0,0) or the end point (0,24). obviously (0,0) is easier to calculate:
0=a(0-12)² +6
a=-1/24
so the quadratic equation is y=- $\frac{1}{24} (x-12)^2+6$

5 0

3 years ago

A particular circle in the standard (x,y) coordinate

matrenka [14]

For any circle with Cartesian equation
$(x-a)^2 + (y-b)^2 = r^2$ ,
we have that the centre of the circle is $(a,b)$ , and the radius of the circle is $r$ .

So in the case that
$(x-5)^2 + y^2 = 38$ ,
we essentially have that
$a = 5, b = 0, r^2 = 38$ .

So the centre of the circle is $(5,0)$ , and the radius is $\sqrt{38}$ .

7 0

3 years ago