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liraira [26]
2 years ago
11

A pyramid has a square base of length 4.8 m and a total surface area of 85 m². Find the volume of the pyramid.​

Mathematics
1 answer:
7nadin3 [17]2 years ago
8 0

Answer:

164.33 m^3

Step-by-step explanation:

Mathematically, we have the formula for the volume as;

V = A * h/3

V = 5.8 * 85/3

V = 164.33 m^3

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The graph shows the amount of rainfall in a town in July over a
Rus_ich [418]

Answer:30%

Step-by-step explanation:

4 0
3 years ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
Please help!!! Please hellp me i do not know the answr to this question.
Alchen [17]

Answer:

77.7

Step-by-step explanation:

First all the angles add up to 360°. You would subtract 180 from the 360 because of the 2 right angles. That leaves you with 180. Then 180-102.3 to get 77.7°, your answer.

3 0
2 years ago
Read 2 more answers
What is lcm of 21, 45 , and 6?
eimsori [14]
21,45,6
21=3*7
45=3*3*5
6=3*2
LCM= 3*3*7*5*2
LCM=630

8 0
3 years ago
one cubic foot of chemical weighs 60 pounds. How many pounds of the chemical can a container withe these dimensions hold? Pictur
Goshia [24]

Answer:

3600 pounds

Step-by-step explanation:

One cubic foot of a chemical weighs 60 pounds.

1 ft³ of chemical = 60 pounds

We need to find how many pounds in the container whose dimension 6 ft, 4 ft and 2.5 ft

l = 6 ft

b = 4 ft

h = 2.5 ft

Volume of box = lbh

                        = 6 x 4 x 2.5

                        = 60 ft³

As we are given

1 ft³ of chemical = 60 pounds

60 ft³ of chemical = 60 x 60 = 3600 pounds

8 0
2 years ago
Read 2 more answers
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