4/5. hopefully this helps
Answer:
7miles
equations shown in work image below
work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)
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Step-by-step explanation:
For both d=r*t
Each bikes to others house and leave at the same time so for Tony,
11 = 30*t
t= 11/30 hours
for Gerry,
11 = 25*t
t= 11/25 hours
Comparing these, with LCD,
Tony's time is 55/150
Gerry's time is 66/150
So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.
Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.
We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150
Answer:
150
Step-by-step explanation:
add three x plus 30 get 30 then add 6y plus 120 and get 120 add them and get 150
So first, I would assign the small van a variable for how many people it can hold, or x.
So since it makes two trips,
2x
And since the other van can hold six more people,
2x + x + 6
And 57 people are transported:
3x + 6 = 57
We can then solve.
3x = 57 - 6
3x = 51
x = 17
So since we now know a small can hold 17 people, and we know that the larger van has 6 more seats, we can just say
17 + 6 = 23
So the large van has 23 seats.