The transaction history at an electronic goods store indicates that 21 percent of customers purchase the extended warranty when
they buy an eligible item. Suppose customers who buy eligible items are chosen at random one at a time, until one is found who purchased the extended warranty. Let the random variable X represent the number of customers it takes to find one who
purchased the extended warranty. Assume customers' decisions on whether to purchase the extended warranty are independentWhich of the following is closest to the probability that X > 3;
that is, the probability that it takes more than 3 customers who buy an eligible item to find one who purchased the extended warranty?
The MAD of January is 8. You can figure this out by finding the mean of the data (adding them all together then dividing by the number of data points), then finding the distance between each data point and the mean. You then will add all the distances together, then divide by the number of data points. The MAD of July is 2.5. See above for the process.