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2 years ago

Alice spins a spinner and rolls a number cube labeled 1-6. the spinner and number cube are shown.

Mathematics

1 answer:

Delicious77 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

first count up the numbers on the spinner and the die cut out the number till get the number but i will guess 2

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Factor the expression completely. 9x+6

Kamila [148]

Answer:

3(3x+2)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A school is preparing a trip for 400 students. The company who is providing the transportation has 10 buses of 50 seats each and

Naya [18.7K]

<h2>The number of small buses used = 5</h2><h2>The number of big buses used = 4</h2>

Step-by-step explanation:

Let us assume the total number of small buses needed = x

The capacity of 1 small bus = 40

So, the capacity of x buses = 40(x) = 40 x

Let us assume the total number of big buses needed = y

The capacity of 1 big bus = 50

So, the capacity of y buses = 50(y) = 50 y

Also, the total students travelling = 400

So, the number of students traveling by (Small bus + Big bus) = 400

⇒ 40 x + 50 y = 400 ..... (1)

Also, the total number of drivers available = 9

⇒ x + y = 9 ..... (2)

Also, x ≤ 8, y ≤ 10

Now, solving both equations, we get:

40 x + 50 y = 400 ..... (1)

x + y = 9 ⇒ y = (9-x) put in (1)

40 x + 50 y = 400 ⇒ 40 x + 50 (9-x) = 400

or, 40 x + 450 - 50 x = 400

or, - 10 x =- 50

or, x = 5 ⇒ y = (9-x) = 9- 5 = 4

Hence the number of small buses used = 5

The number of big buses used = 4

8 0

3 years ago

Find the value of x and the value of y.

astra-53 [7]

The answer is C : x = 2 rad 2 and y= 2 rad 3

4 0

3 years ago

I need help on these ASAP THX

Kisachek [45]

Answer: The third one or C

4 0

2 years ago

Among 420 randomly selected employees at a company, the mean number of hours of overtime worked per month is 10 hours and the st

kari74 [83]

The margin of error of the random selection is 0.20

The given parameters are:

$n = 420$ --- the sample size

$\sigma = 1.6$ --- the standard deviation

$\bar x = 10$ --- the mean

$\alpha = 99\%$ --- the confidence level.

The margin of error (E) is calculated as follows:

$E = z \times \sqrt{\frac{\sigma^2}{n}}$

So, we have:

$E = z \times \sqrt{\frac{1.6^2}{420}}$

$E = z \times \sqrt{\frac{2.56}{420}}$

The z-value for 99% confidence level is 2.576.

Substitute 2.576 for z

$E = 2.576 \times \sqrt{\frac{2.56}{420}}$

$E = 2.576 \times \sqrt{0.006095}$

Take square roots

$E = 2.576 \times 0.0781$

Multiply

$E = 0.2012$

Approximate

$E = 0.20$

Hence, the margin of error is 0.20