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OLEGan [10]
3 years ago
12

Solve the following triangles, Round to the nearest tenth

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0

Answer:

I think B=25

Step-by-step explanation:

take 180-130-25=25

dalvyx [7]3 years ago
5 0

Answer:

B = 180 - 130 - 25 = 25

a = 6

c = 10.9

Step-by-step explanation:

the sum of all angles in a triangle is always 180 degrees.

so, we know 2 angles. we need to subtract them from 180 to get the third angle.

as it turns out, the angles at A and B are equal, and that means that also the corresponding side lengths must be equal : a = b = 6.

and for c we use the general Pythagoras

c² = a² + b² - 2ab×cos(C)

c² = 36 + 36 - 72×cos(130) = 118.28...

c = sqrt(118.28...) = 10.87569344... ≈ 10.9

just in case

36 + 36 - 72×cos(130) = 72 - 72×-0.64... =

= 72 + 72×0.64... = 118.28...

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(Writing Two-Step Equations HC) Given the equation 4x + 12 = 64: Part A: Write a short word problem about a purchase made to ill
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Considering the expression 4x + 12 = 64, it is found that:

A. The problem is that you purchased x fried pastry, costing $4, plus a chocolate and a soda, costing $12, and the total purchase cost was of $64.

B. The solution is x = 13.

C. The solution means that you purchased 13 fried pastry.

<h3>Expression</h3>


The expression is presented as follows:

4x + 12 = 64.

A possible context for this problem is:

  • x fried pastry are purchased, each costing $4, hence 4x.
  • A chocolate and a soda purchased, costing a total of 12, hence 4x + 12.
  • The total cost of the purchase was of $64, hence 4x + 12 = 64.

The number of fried pastry purchased is the solution to the equation, calculated as follows:

4x + 12 = 64

4x = 52

x = 52/4

x = 13 -> 13 fried pastry were purchased.

More can be learned about expressions at brainly.com/question/24342899

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2 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
4 years ago
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