<span>(19/76)x100=25% have seen the film</span>
3 1/4 + 2 1/3 = 67/
12
= 5 7/12
Mark brainliest please
Hope this helps you
Considering the expression 4x + 12 = 64, it is found that:
A. The problem is that you purchased x fried pastry, costing $4, plus a chocolate and a soda, costing $12, and the total purchase cost was of $64.
B. The solution is x = 13.
C. The solution means that you purchased 13 fried pastry.
<h3>Expression</h3>
The expression is presented as follows:
4x + 12 = 64.
A possible context for this problem is:
- x fried pastry are purchased, each costing $4, hence 4x.
- A chocolate and a soda purchased, costing a total of 12, hence 4x + 12.
- The total cost of the purchase was of $64, hence 4x + 12 = 64.
The number of fried pastry purchased is the solution to the equation, calculated as follows:
4x + 12 = 64
4x = 52
x = 52/4
x = 13 -> 13 fried pastry were purchased.
More can be learned about expressions at brainly.com/question/24342899
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Answer:
a) 
b) 
And replacing we got:
![P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.2%2B0.3%2B0.1%5D%3D%200.4)
c) 
d) 
e) 
f) 
And replacing we got:

And the variance would be:
![Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4](https://tex.z-dn.net/?f=%20Var%28X0%20%3DE%28X%5E2%29-%20%5BE%28X%29%5D%5E2%20%3D%206.4%20-%282%5E2%29%3D%202.4)
And the deviation:

Step-by-step explanation:
We have the following distribution
x 0 1 2 3 4
P(x) 0.2 0.3 0.1 0.1 0.3
Part a
For this case:

Part b
We want this probability:

And replacing we got:
![P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.2%2B0.3%2B0.1%5D%3D%200.4)
Part c
For this case we want this probability:

Part d

Part e
We can find the mean with this formula:

And replacing we got:

Part f
We can find the second moment with this formula

And replacing we got:

And the variance would be:
![Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4](https://tex.z-dn.net/?f=%20Var%28X0%20%3DE%28X%5E2%29-%20%5BE%28X%29%5D%5E2%20%3D%206.4%20-%282%5E2%29%3D%202.4)
And the deviation:
