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2 years ago

Find the length of each arc. Round your answers to the nearest tenth.

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

8 0

Answer: 7.1 yd

Step-by-step explanation:

the formula for arc length is 2πr(x/360), x being the central angle

input the values, so the equation would be 2π9(45/360), which equals 7.1

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Heidi has an average score of 78 for her first six chemistry tests. If Heidi"s scores for the first four tests were 82,78,87, an

elixir [45]

Answer:

(A)74

Explanation:

Let her average score on the last two tests = x.

The six scores will now be: 82,78,87,73, x and x.

Since the average score for her first six chemistry tests = 78

$\frac{82+78+87+73+x+x}{6}=78$

We then solve for x.

$\begin{gathered} 320+2x=78\times6 \\ 320+2x=468 \\ 2x=468-320 \\ 2x=148 \\ x=\frac{148}{2} \\ x=74 \end{gathered}$

Her average score for the last two tests is 74.

3 0

1 year ago

Perform the following operations s and prove closure. Show your work.

nadezda [96]

Answer:

1. $\frac{x}{x+3}+\frac{x+2}{x+5}$ = $\frac{2x^2+10x+6}{(x+3)(x+5)}\\$

2. $\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}$ = $\frac{1}{(x+2)(x-4)}$

3. $\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}$ = $\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}$

4. $\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}$ = $\frac{1}{(x-2)(x-4)}$

Step-by-step explanation:

1. $\frac{x}{x+3}+\frac{x+2}{x+5}$

Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

$=\frac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}\\=\frac{x^2+5x+(x)(x+3)+2(x+3)}{(x+3)(x+5)} \\=\frac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)} \\=\frac{x^2+x^2+5x+3x+2x+6}{(x+3)(x+5)} \\=\frac{2x^2+10x+6}{(x+3)(x+5)}\\$

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.

2. $\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}$

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)

Putting factors

$=\frac{x+4}{(x+3)(x+2)}*\frac{x+3}{(x-4)(x+4)}\\\\=\frac{1}{(x+2)(x-4)}$

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.

3. $\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}$

Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)

Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)

Putting factors

$\frac{2}{(x+3)(x-3)}-\frac{3x}{(x+3)(x-2)}$

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)

$\frac{2(x-2)-3x(x+3)(x-3)}{(x+3)(x-3)(x-2)}$

$=\frac{2(x-2)-3x(x+3)}{(x+3)(x-3)(x-2)}\\=\frac{2x-4-3x^2-9x}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-9x+2x-4}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}$

Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.

4. $\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}$

Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

$\frac{x+4}{(x-2)(x+3)}\div\frac{(x-4)(x+4)}{x+3}$

Converting ÷ sign into multiplication we will take reciprocal of the second term

$=\frac{x+4}{(x-2)(x+3)}*\frac{x+3}{(x-4)(x+4)}\\=\frac{1}{(x-2)(x-4)}$

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.

5 0

3 years ago

5(x-7) = 6(x+2)<br>please help ... I got 11x = -23??

eimsori [14]

Answer:

$x = -47$

Step-by-step explanation:

1. Use the distributive property

5 ( x - 7 ) = 6 ( x + 2 ) → 5x - 35 = 6x + 12

2. Subtract 5x from both sides of the equation

5x - 5x -35 = 6x - 5x + 12 → -35 = x + 12

3. Subtract 12 from both sides

-35 - 12 = x + 12 - 12 → -47 = x

4. So, the answer is

$x = -47$

4 0

2 years ago

What is the total surface area of the

GaryK [48]

Answer:468 in2

Step-by-step explanation:

7 0

3 years ago

What can you weave into your game in order to make it easier to pinpoint a particular audience?

Viktor [21]

Answer:

B. A secret cheat

Step-by-step explanation:

Correct me if i am wrong

6 0

2 years ago