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3 years ago

What is 8/10 x 3 2/3 in simplest form

Mathematics

2 answers:

erica [24]3 years ago

6 0

Answer:

idk but you fine asl

Step-by-step explanation:

sasho [114]3 years ago

6 0

Hey the answer is 128/15, the answer can be simplified! :)

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According to an IRS study, it takes a mean of 330 minutes for taxpayers to prepare, copy, and electronically file a 1040 tax for

Goryan [66]

Answer:

Your question is step-by-step solved.

Step-by-step explanation:

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2 years ago

Todd Holland from NY grows pumpkins. He studied his past records carefully and concluded that his biggest pumpkins are distribut

ehidna [41]

Answer:

$P(X>1000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>1000)=P(\frac{X-\mu}{\sigma}>\frac{1000-\mu}{\sigma})=P(Z>\frac{1000-950}{50})=P(z>1)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>1)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(950,50)$

Where $\mu=950$ and $\sigma=50$

We are interested on this probability

$P(X>1000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>1000)=P(\frac{X-\mu}{\sigma}>\frac{1000-\mu}{\sigma})=P(Z>\frac{1000-950}{50})=P(z>1)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>1)=1-P(z$

5 0

3 years ago

|x-1| if x>1<br> how do you simplify this

JulsSmile [24]

Use the definition of absolute value.

$|x| = \begin{cases} x & \text{if } x \ge0 \\ -x & \text{if } x < 0 \end{cases}$

The absolute value is always non-negative. So if $x$ is already non-negative, $|x|=x$ is unchanged. But if $x$ is negative, then $|x|=-x$ because multiplying $x$ by -1 makes it positive.