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2 years ago

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Mathematics

2 answers:

gayaneshka [121]2 years ago

8 0

Answer:

then

Step-by-step explanation:

butalik [34]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Giselle made 24 1/8 ounces of lemonade. She sampled 1 1/2 ounces to make sure it is not too sour. How much lemonade is left? Exp

vivado [14]

step.1 turn both of the numbers into fraction

24x8=192, because 8 out of 8 is 1. Plus one equals to 193/8

1x2=2 plus 1 equals to 3. 3/2

step.2 turn the bottom numver the same

because 2x4 is 8 from the bottom

3x4 is 12 so the lemonade she sampled is 12/8

step.3 substract

193/8-12/8you keep the bottom the same substract the top.

193-12

the answer is : 181/8

8 0

2 years ago

Figure b is a scale image of Figure A, as shown. Figure a is an Rectangle with 9 on left side and 12 on bottom of rectangle. and

Ronch [10]

The scale factor that was applied to figure A to produce figure B is: 11/3 = 3.67.

<h3>How to Find the Scale Factor of a Dilation?</h3>

The ratio of the corresponding dimensions of the image to the preimage gives the scale factor of any dilation.

That is:

Scale factor = dimension of image (new figure) / corresponding dimension of pre-image (original figure).

The scale factor that was applied to figure A to produce figure B = dimension of figure B / corresponding dimension of figure A.

A dimension of figure B = 33

Corresponding dimension of figure A = 9

Therefore, we would find the scale factor as shown below:

The scale factor that was applied to figure A to produce figure B = 33/9

= 11/3 = 3.67

Therefore, the scale factor that was applied to figure A to produce figure B is: 11/3 = 3.67.

Learn more about the scale factor on:

brainly.com/question/2826496

#SPJ1

6 0

11 months ago

1.Assume that 20 squirrels are put in an enclosed wildlife ranch and the squirrel population grows for the next 5 years, as show

stiv31 [10]

Answer:

For the first group we have the pairs:

year population

0 20

1 80

2 320

3 1,280

4 5,120

5 20,480

Here we can see that the population quadruples each year

(4*20 = 80, 80*4 = 320, 320*4 = 1,280, etc...)

then the population equation is:

P(0) = 20

P(1) = 20*4

P(2) = (20*4)*4 = 20*4^2

We already can see the pattern, then we can write this relationship as:

P(t) = A*(4)^(t)

Where:

t represents time in years, and A is the initial population, that we know it is 20, then:

P(t) = 20*(4)^t

This is the function that represents the table.

B) Now we have a group of 20 squirrels and the population triples each year, with the same reasoning than before we can write the equation that models this situation as:

Q(t) = 20*(3)^t

C) Now, if the initial population of the second group is 40, the equation becomes:

Q(t) = 40*(3)^t

The population by year 3 is given by replacing t by 3, then:

Q(3) = 40*(3)^3 = 1080

And the population of the other group in year 3 is seen in the table, it is 1,280, then the population of the first group is bigger by year 3, and it is greater by:

1,280 - 1,080 = 200

So the first group is larger by 200 squirrels.

3 0

2 years ago

An arithmetic

Sunny_sXe [5.5K]

Answer:

an = 7.5 - 5.5(n - 1).

Step-by-step explanation:

The common difference d = -5.5.

The first term is given as 7.5.

Explicit formula is

an = a1 + (n - 1)d

= 7.5 + (n - 1)-5.5

= 7.5 - 5.5(n - 1)

8 0

2 years ago

5. a : 4, for a = 32

Dmitrij [34]

Answer:

Step-by-step explanation:

put 4 in place for a

4=32

dive both sides by 4 and you will get 8

hope this helps

8 0

2 years ago