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aniked [119]
3 years ago
14

Can anyone help me solve this?​

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer:

Step-by-step explanation:

(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35

Simplify:

(\sqrt{z})^{2} -57=0

Factor (\sqrt{z})^{2}  -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})=0

\sqrt{z} +\sqrt{57}=0    or    \sqrt{z}  -\sqrt{57}=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

\sqrt{z} -\sqrt{57} =0: z=57

Your answer will be z=57

and No solution

dsp733 years ago
3 0

Answer:

(

z

+

22

)(

z

−

22

)=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35(

z

+

22

(

z

−

22

)−35=35−35

Simplify:

(\sqrt{z})^{2} -57=0(

z

)

2

−57=0

Factor (\sqrt{z})^{2} -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})(

z

)

2

−57:(

z

+

57

)(

z

−

57

) =0

\sqrt{z} +\sqrt{57}=0 or \sqrt{z} -\sqrt{57}=0

z

+

57

=0or

z

−

57

=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

z

+

57

=0:NoSolutionforZ

\sqrt{z} -\sqrt{57} =0: z=57

z

−

57

=0:z=57

Your answer will be z=57

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Answer:

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Let

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x ---> the number of snakes

y ---> the number of lizards

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The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

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isolate the variable x

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solve the system by substitution

substitute equation A in equation B

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solve for y

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y=8\ lizards

Find the value of x

x=1.5(8)=12\ snakes

therefore

12 snakes and 8 lizards

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