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2 years ago

Plz help me well mark brainliest if you are correct!!....

Mathematics

2 answers:

NeTakaya2 years ago

5 0

Answer:

Step-by-step explanation:

the two lines on either sign of each number indicate absolute value, which is the numbers value from 0 (on a number line). You turn -12 and -3 into 12 and 3 and subtract as normal.

sweet-ann [11.9K]2 years ago

3 0

|-12| - |-3| = 9
The absolute value of -12 is 12 and the absolute value of -3 is 3. So, |-12| - |-3| = 12 - 3 = 9

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A committee must be formed with 5 teachers and 4 students. If there are 6 teachers to choose from, and 15 students, how many dif

ZanzabumX [31]

Answer:

8190 ways

Step-by-step explanation:

Given

$Teachers = 6$

$Students = 15$

Selection

$Students = 4$

$Teachers = 5$

Required

Number of ways of selection

4 students can be selected from 15 students in:

$Students= ^{15}C_4$

Similarly.

5 teachers can be selected from 6 teachers in:

$Teachers= ^{6}C_5$

So, the required number of selection is:

$Selection = ^{15}C_4 * ^6C_5$

Apply combination formula:

$Selection = \frac{15!}{(15-4)!4!} * \frac{6!}{(6-5)!5!}$

$Selection = \frac{15!}{11!4!} * \frac{6!}{1!5!}$

$Selection = \frac{15*14*13*12*11!}{11!*4*3*2*1} * \frac{6*5!}{1*5!}$

$Selection = \frac{15*14*13*12}{4*3*2*1} * \frac{6}{1}$

$Selection = \frac{32760}{24} * 6$

$Selection = 1365 * 6$

$Selection = 8190$

8 0

3 years ago

Which expressions are equivalent to 5(1/3x+7)-3(1/2x-4)? Select three options. (There’s a picture)

Otrada [13]

3rd option

Step-by-step explanation:

solve and simplify to find

7 0

3 years ago

What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?

mars1129 [50]

The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
$S_{n}=\frac{a_{1}(1-r^{n})}{1-r}$
a1=1
r=2
we want to find $S_{10}$ (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

$S_{10}=\frac{1(1-2^{10})}{1-2}$
$S_{10}=\frac{(1-1024}{-1}$
$S_{10}=\frac{(-1023}{-1}$
$S_{10}=1023$

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DENIUS [597]

Wouldn't you just round

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Marrrta [24]

Here is the formula: b•h/2

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