Answer:
Step-by-step explanation:
Answer:
D) He calculated the joint relative frequency of female students who prefer playing sports. The conditional relative frequency for female students who prefer playing sports is 34%.
Step-by-step explanation:
The table is given as:
Playing sports Dancing Row totals
Male students 18 16 34
Female students 18 35 53
Column totals 36 51 87
- We know that the joint relative frequency of an outcome is calculated as dividing the frequency of the outcome by the grand total.
Hence, when we divide the frequency of the female students who prefer playing sports i.e. 18 by the grand total i.e. 87 ; we obtain:
18/87=0.20689
which is approximately equal to 21%.
- Hence, in order to calculate the conditional relative frequencies she should have divided the required frequency by the row total;.
Hence, here we divide the frequency of the female students who prefer playing sports i.e. 18 by the row total i.e. 53 ; we obtain:
18/53-0.3396
which is approximately equal to 34%.
Hence, option: D is correct.
Answer:
F(X) > 0 over the interval (-infinity, -4)
Step-by-step explanation:
F(x) is the function and really can be written like y. As you can see from the graph, between -4 and -infinity the graph is constantly increasing and will never decrease below zero again, therefore D (the 4th statement) is the correct one.
What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
Answer:
8
Step-by-step explanation:
