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3 years ago

If you answer right good review

Mathematics

2 answers:

horsena [70]3 years ago

3 0

3rd one... the one below the first option gl

Alinara [238K]3 years ago

3 0

Answer:

the line crosses the y axis below the origin.

Step-by-step explanation:

native y intercept

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Substitution for y=3x-34 and y=2x-5

Lelu [443]

Y=3x-34
y=2x-5
both are equal to y

3x-34=y=2x-5
3x-34=2x-5
minus 2x both sides
x-34=-5
add 34both sides
x=29

sub back

y=2x-5
y=2(29)-5
y=58-5
y=53

x=29
y=53
(29,53)

8 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

Classify the following triangle check all that apply

Mademuasel [1]

Answer:

Right, Acute, Scalene.

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

A cube box has a side length of 7 feet . what is the total surface area of the mix?

Tomtit [17]

Answer:

294

Step-by-step explanation:

SA = 6 $x^{2}$

= 6 ( $7^{2}$ )

294 = 6 (49)

5 0

3 years ago

Unknown plz plz help me

scoundrel [369]

144m^2 because the area of each triangle is 27m^2, so 27x4 is 108, then you add the 36 for the base to get 144

8 0

3 years ago