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Natali5045456 [20]
2 years ago
8

Determine the LCM of 50, 150, and 225. 5 25 50 450

Mathematics
2 answers:
BaLLatris [955]2 years ago
6 0

THE answer is a) 5 :)

velikii [3]2 years ago
3 0
The answer for this question is (a)5

Hope it helps!
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Answer:

y=-\frac{6}{5} x

Step-by-step explanation:

y=-6/5x+0

y=-6/5x

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Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

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2 years ago
a scale drawing of a building needs to be made using the scale 1 in = 190 ft. how tall will the builging in the scale drawing be
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Answer:

\boxed{\text{3 in}}

Step-by-step explanation:

1 in = 190 ft

x in = 570 ft

We can use ratio and proportion to solve this problem.

\begin{array}{cccl}\dfrac{1}{x} & = & \dfrac{190}{570} & \\\\570 & = & 190x & \text{Mutiplied by lowest common denominator (570x)}\\3 & = & x & \text{Divided each side by 3}\\\end{array}

The building will be \boxed{\textbf{3 in}} tall in the scale drawing.

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3 years ago
I am confused with everything
notsponge [240]
I think it's x^3+2x^2-4
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