Answer:
The maximum possible area of the pasture = 2450 square feet
Step-by-step explanation:
Let the length of the creek be 'L'
and, the width of the rectangular area be 'B'
Data provided:
The rectangular area is enclosed using the creek as one side and fencing for the other three sides
Thus, 2B + L = 140 feet
or
L = 140 - 2B .........(1)
Now,
Area of the rectangular land, A = L × B
using (1)
A = ( 140 - 2B) × B
or
A = 140B - 2B²
Now to maximize the area, differentiating the area with respect to width 'B'
we have
= 140 - 2 × 2 × B ...........(2)
for point of maxima or minima , = 0
thus,
140 - 2 × 2 × B = 0
or
4B = 140
or
B = 35 feet
differentiating (2) with respect to B, for verifying the maxima or minima
= 0 - 2 × 2 = -4
since, is negative,
therefore,
B = 35 feet is point of maxima
from (1)
L = 140 - 2B
or
L = 140 - 2 × 35
or
L = 140 - 70 = 70 feet
Hence,
The maximum possible area of the pasture = L × B
= 70 × 35
= 2450 square feet
Answer:
Step-by-step explanation:
x=
x=
x=2
Answer:
b
Step-by-step explanation:
Answer:
<u><em>x^2 + 8x + 12</em></u>
Step-by-step explanation:
The area is in 4 parts:
x * x,
x * 2,
6 * x, and
2 * 6
So it is x^2 + 2x + 6x + 12, or
x^2 + 8x + 12
Given:
<span>F= $335,000
n = 30 years at a fixed rate of i = 7.5%
Required:
the total cost of the principal
Solution:
F = P(1+i)^n
P = F/(1+i)^n
P = 335,000 / (1.0.075)^30
P = 38,264.05</span>