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kakasveta [241]
2 years ago
9

Diego want to paint his room purple. He bought one gallon of purple paint that is 30% red paints and 70% blue paints. Diego want

s to add more blue to mix that the paint mixture is 20% red, 80% blue.
How much blue paint should Diego add? Test the following possibilities: 0.2 gallons, 0.3 gallons
Mathematics
1 answer:
solniwko [45]2 years ago
8 0

Answer:

10 gallons

Step-by-step explanation:

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Volume= 125cm cubed
Total Surface area=150 cm squared
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1. 5 • 2/3 as an improper fraction in simplified form.
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1.3.33

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2 years ago
Which equation in point-slope form contains the point (4, –1) and has slope 3?
Andrew [12]

Answer:

y+1=3(x-4)

Step-by-step explanation:

Hi there!

We are given a slope of 3 and a point (4,-1).

We need to find the equation of the line in point-slope form

Point-slope form is given as y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point

We have all of the needed information to substitute into the formula

First, let's label the values of everything to avoid any confusion

m=3

x1=4

y1=-1

now substitute into the formula *remember, the formula has SUBTRACTION, and we have a NEGATIVE number, so we'll end up subtracting a negative*

y--1=3(x-4)

simplify

y+1=3(x-4)

That's it!

Hope this helps :)

4 0
3 years ago
A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t
Molodets [167]

Answer:

940.8 N

1254.4 N

Step-by-step explanation:

I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:

On the top:

F = pressure * area

P = density * gravity * height

the height would be:

1m - 0.4m = 0.6m

replacing:

P = 1000 * 9.8 * 0.6 = 5880

A = (0.4) ^ 2 = 0.16

F = 5880 * 0.16

F = 940.8 N

On the sides:

dF = d * g * h * dA

dA = 0.4 * dh replacing

dF = 1000 * 9.8 * h * 0.4 * dh

dF = 3920 * h * dh

We integrate both sides and we have:

F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1

F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)

F = 1254.4 N

3 0
3 years ago
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