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kakasveta [241]
2 years ago
9

Diego want to paint his room purple. He bought one gallon of purple paint that is 30% red paints and 70% blue paints. Diego want

s to add more blue to mix that the paint mixture is 20% red, 80% blue.
How much blue paint should Diego add? Test the following possibilities: 0.2 gallons, 0.3 gallons
Mathematics
1 answer:
solniwko [45]2 years ago
8 0

Answer:

10 gallons

Step-by-step explanation:

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What are the steps to solving this equation <br><br>7x+3= 9x-3-2x
Luba_88 [7]
Simplify:

7x+3=7x-3

Now 7x goes away and you get 3=-3, which cannot be true, so there is no solution
7 0
2 years ago
PLZ HELP PLZ HELP brainlyist for correct answer
Amiraneli [1.4K]
So you basically plug in the x value beside the 5 so if your on number 3 the answer would be 5(3) which is 15

4 0
3 years ago
It’s asking for the area<br> Please help! Thank you!
Eddi Din [679]

Answer: x^2+9x+20

Step-by-step explanation:

To find the area you multiply the sides so it should be (x+4)(x+5) which is x^2+9x+20. Good luck!

6 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
Having trouble with this one can somebody help?
Varvara68 [4.7K]
Form equation
y = mx + c
y = (rise/run).x + c
y = (11-1 / 3--2)x + c
y = 2x + c
11 = 2(3) + c
Find c (y-intercept)
11 - 6 = c
c = 5
Final equation of line
y = 2x + 5
Substitute given possible x-values in to find y-values
y = 2(1) + 5 = 7 (1,7)
y = 2(2) + 5 = 9 (2,9)
Therefore d is correct
3 0
2 years ago
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