Answer:
D
Step-by-step explanation:
Let's solve your equation step-by-step.
−4y+4y+2=2
Step 1: Simplify both sides of the equation.
−4y+4y+2=2
(−4y+4y)+(2)=2(Combine Like Terms)
2=2
2=2
Step 2: Subtract 2 from both sides.
2−2=2−2
0=0
Answer:
All real numbers are solutions.
The perimeter would be about 34.4 because if you choose the bottom side to be ten, by multiplying 35 by 2 to get 70 you can divide by 10 to get 7. Since you know the height and width, you can use pythagorean theorem, a^2 + b^2 = c^2. Plug in the numbers you have 10^2+7^2=c^2. c^2=149, so if you square root 149 you will get a irrational number but when rounded you get 12.2- so that is one side multiply by 2 and get 24.4- and add 10 to get 34.4
Answer: 1.2
Step-by-step explanation:
Let X denotes the grades on a language midterm at Oak Academy.
As per given ,
X follows normal distribution ( because it has symmetric graph)
Formula for z : 
For X = 70, we have
Hence, the z-score for Ishaan's exam grade = 1.2
9. sensitive noses, big ears, and long tail.
10. ferns, yeasts, hydras, and amoebas
Answer:
At 25 = 6.8612mm
At 50 years = 5.422mm
Step-by-step explanation:
Equation,
d = 2.115Logₑa + 13.669
d = diameter of the pupil
a = number of years
Note : Logₑa = In a (check logarithmic rule)
d = 2.115Ina + 13.669
1. At 25 years,
d = -2.115In25 + 13.669
d = -2.115 × 3.2188 + 13.669
d = -6.807762 + 13.669
d = 6.8612mm
At 25 years, the pupil shrinks by 6.86mm
2. At 50 years,
d = -2.1158In50 + 13.669
d = -2.1158 * 3.912 + 13.669
d = -8.2770 + 13.699
d = 5.422mm
At 50 years, the pupil shirks by 5.422mm
To save this question, I had to plug in the values into the equation.
Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.
