2 years ago

Find the equation of the line that is perpendicular to the given line and passes through the given point.

Mathematics

1 answer:

liberstina [14]2 years ago

4 0

Y= -1/5x-3
Y= -1/5x0-3
Y=-3

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Use algebraic means to show that x^2 + y^2 = 8 is not a function. Explain your process.

11Alexandr11 [23.1K]

Answer:

For a single value of x function has more than one corresponding value of y which satisfies the equation.

Step-by-step explanation:

Function: A relationship between a set of inputs and a set of possible outputs, where exactly one output is associated with each input.

It means for an equation to represent a function any single value of x there should be only one corresponding value of y which satisfies the equation.

Now consider the given equation.

$x^2 + y^2 = 8$

If we put x=0 then we get two value of y i.e $\sqrt8$ and $-\sqrt8$ which satisfy the equation and therefore the equation is not a function.