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DaniilM [7]
2 years ago
5

Find the equation of the line that is perpendicular to the given line and passes through the given point.

Mathematics
1 answer:
liberstina [14]2 years ago
4 0
Y= -1/5x-3
Y= -1/5x0-3
Y=-3
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Please help I only have 15 minutes to complete this last one
Natalka [10]

Answer:

the slope of MN= -5-1/3-(-6)=-2/3

two lines are parallel>> slopes are equal

equation of line = (y-y'=m(x-x'))

therefore, y-1= -2/3(x-6)

y-1 = -2/3x + 4

y+2/3x=5

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3 years ago
For which value of x is the figure a rhombus?
zysi [14]

Answer:

D. x = 7

Step-by-step explanation:

The labeled angles are the acute angles of a right triangle, so they are complementary. Their measures add up to 90 deg.

8x + 7 + 3x + 6 = 90

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3 0
3 years ago
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dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

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t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

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Enid has to pay the employment agency $625
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i need more information on this

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