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2 years ago

5x - (x - 16) = 2x - (_) + x)

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

5 0

Answer:

x=1

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation 16-2*x-(5*x+9)=0

Pull out like factors : 7 - 7x = -7 • (x - 1)

Solve : -7 = 0 This equation has no solution.

A a non-zero constant never equals zero.

Solve : x-1 = 0 Add 1 to both sides of the equation :

x = 1

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Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

tankabanditka [31]

5k3-3k+7-(-2k3+k2-9)
basically rewrite with simple algebra principles
15k-3k+7-(-6k+2k-9)
split up the parenthesis
15k-3k+7+6k-2k+9
sort them
15k-3k+6k-3k+7+9
short down by adding up the similar factors
answer: 18k+18
factorise
18(k+1)
both forms are right

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2 years ago

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Zach bought two jet skis for 15,480. He will make 36 payments. How much will each payment be?

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3 years ago

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What is the quotient of 1,387÷19?

Rus_ich [418]

73

73 * 19 = 1,387

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2 years ago

Pearl deposited $60 into her savings account. According to the rule of 72, what interest rate will cause her money to double in

statuscvo [17]

Answer:2.2%

Step-by-step explanation:

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2 years ago

10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

$\displaystyle{csc(x)= \frac{1}{sin(x)}$

Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

$\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\$

$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

$cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)$

Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

which is equal to $csc(\theta)$ , by identity 3

Answer: D

7 0

3 years ago