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seraphim [82]
3 years ago
13

Whats the circumference of a circle with a diameter of 30 centimeters

Mathematics
2 answers:
Bingel [31]3 years ago
8 0
<span>94.25 centimeters is your answer. Hope this helps!</span>
Yuki888 [10]3 years ago
4 0
Well you have to find the radius you have to divide the diameter by 2 which will get you 15. the equation to find circumference is c=2PIEr (sorry didn't have the pie symbol). Anyways just plug in the numbers and you get you answer. Hope this help.
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Due to a bad crop year, the cost of cherries is projected to increase 133% this year. A pound of cherries currently costs $2.16.
aliya0001 [1]
To solve this problem, or one of sorts, you can multiply the current price (2.16) by 1.33 (the percentage as a decimal).

2.16*1.33 = 2.8728

Round to two decimal places (and that’s the number of decimal places for money), and you can expect the new price per pound of cherries to be about $2.87.
6 0
3 years ago
Find the volume of the triangular prism.
pychu [463]
Find the area of the triangle shaped faces. The area of a triangle is b•h/2
7•2=14/2=7
then multiply it by 4.5,

the area is 31.5 in^2
3 0
3 years ago
What number can go in 52 &amp; 13
Blababa [14]

Answer:

13 can go into 52.

Step-by-step explanation:

52/13=4

8 0
3 years ago
Some 1 plz HELP!<br> 3 5/6 X 4 4/5<br> (plz include instructions if u can thx!)
rewona [7]
Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is 
552
8 0
3 years ago
Read 2 more answers
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra
Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

z=1

\frac{dx}{dt}=430

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

y=2

According to Pythagoras

hypotenuse^2=base^2+perpendicular^2

y^2=x^2+1^2

y^2=x^2+1               .... (1)

Put z=1 and y=2, to find the value of x.

2^2=x^2+1^2

4=x^2+1

4-1=x^2

3=x^2

Taking square root both sides.

\sqrt{3}=x

Differentiate equation (1) with respect to t.

2y\frac{dy}{dt}=2x\frac{dx}{dt}+0

Divide both sides by 2.

y\frac{dy}{dt}=x\frac{dx}{dt}

Put x=\sqrt{3}, y=2, \frac{dx}{dt}=430 in the above equation.

2\frac{dy}{dt}=\sqrt{3}(430)

Divide both sides by 2.

\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}

\frac{dy}{dt}=372.390923627

\frac{dy}{dt}\approx 372

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

6 0
3 years ago
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