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3 years ago

5

ordyn went out to lunch. She likes to tip on the taxed amount. Her meal cost $25. There is a 8% tax and she will leave 20% of ta

xed amount as tip. How much will she pay in total? *

1 answer:

igor_vitrenko [27]3 years ago

5 0

2ok is the answer loliliodbjshdhdgrh to

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If a 4 x 16 rectangle has the same area as a square, what is the length of a side of the square?

Licemer1 [7]

Answer:

Option D. 8 units

Step-by-step explanation:

step 1

Find the area of rectangle

The area of rectangle is

$A=(4)(16)=64\ units^2$

step 2

Find the length side of the square with the same area of rectangle

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=64\ units^2$

substitute

$64=b^2$

take the square root both sides

$b=8\ units$

therefore

The length side of the square is 8 units

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4 years ago

Determine whether the graphs of any of the following equations are parallel or perpendicular. Explain

bixtya [17]

Answer:

y=4x and x+4y=12 are perpendicular because they have opposite reciprocal slopes

Step-by-step explanation:

y=4x slope is 4

x+4y=12 slope is -1/4

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3 years ago

Find the square of each imaginary number.<br> (Get rid of the i)

Dovator [93]

Answer:

- 32/21 over 5 is

Step-by-step explanation:

*gets coins and runs to the store to get "milk"

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3 years ago

Read 2 more answers

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

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3 years ago

Which ordered pairs are solutions to the inequality y−4x≤−6 ?

amid [387]

I think it is A, (-2,-14)

7 0

4 years ago