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ICE Princess25 [194]
3 years ago
12

If the 13th and 38th terms of an arithmetic sequence are -53 and -128,

Mathematics
1 answer:
love history [14]3 years ago
7 0

9514 1404 393

Answer:

  -2018

Step-by-step explanation:

The n-th term is ...

  an = a1 +d(n -1)

So, the given terms are ...

  -53 = a1 +12d

  -128 = a1 +37d

Subtracting the first from the second gives ...

  (a1 +37d) -(a1 +12d) = (-128) -(-53)

  25d = -75

  d = -3

The 668th term will be ...

  a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

  a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

  a668 = -2018

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“Find 24% of $240.”<br><br> I keep trying and getting a different answer each time, please help
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Answer:

$57.60

Step-by-step explanation:

The first thing you want to do is convert 24% to a decimal. To do this you just need to take the current decimal place and move it 2 places to the left. Since this percentage is a whole number the decimal is just after the 4.

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(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
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Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

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