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8090 [49]
3 years ago
15

(x - 5)(5x + 2) = 0 (please help)

Mathematics
2 answers:
barxatty [35]3 years ago
7 0

Answer:

x=-5

Step-by-step explanation:

please tell me if im wrong lol

ikadub [295]3 years ago
7 0

Answer:

(5 , - 0.4)

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Which of the following options correctly describes the graph below
Mazyrski [523]
What’re the options?
6 0
3 years ago
Find the radius of a circle in which a central angle of StartFraction pi Over 7 EndFraction radian determines a sector of area 7
QveST [7]

Answer:

Step-by-step explanation:

The formula for determining the the area of a sector is expressed as

Area of Sector = θ/360 × πr²

Where

θ represents the central angle.

π is a constant whose value is 3.14

r represents the radius of the circle.

From the information given,

The central angle is π/7 radian. Converting to degrees, it becomes

π/7 × 180/π = 180/7 = 25.714 degrees.

Area of sector = 77 square meters

Therefore

77 = 25.714/360 × 3.14 × r²

77 = 0.2243r²

r² = 77/0.2243 = 343.29

r = √343.29 = 18.53 meters

5 0
3 years ago
PLEASE HELP SOON. Answer any amount.
LiRa [457]
No.5=1/3x=21
So x is twenty one21
6 0
3 years ago
PLSSS ANSWER, 35 pointss
xxTIMURxx [149]

Answer:

1.

(y - 5)(x + y)

2.

{(x - y)}(x - y   + a)

3.

(b - 3)(5b - 17)

Step-by-step explanation:

1. The given polynomial is

x(y - 5) - y(5 - y)

We need to factor the second part to get:

x(y - 5)  +  y(y - 5)

We factor y-5 to obtain:

(y - 5)(x + y)

2. We have

{(x - y)}^{2}  - a(y - x)

We again factor -1 from the second part to get:

{(x - y)}^{2} +  a(x- y)

We now factor x-y to get:

{(x - y)}^{2}   + a(x- y)

{(x - y)}(x - y   + a)

3. We have

2(3 - b) + 5 {(b - 3})^{2}

We factor negative 1 from the first part to get

- 2(b - 3) + 5 {(b - 3})^{2}

We now factor b-3 to get:

(b - 3)( - 2 + 5(b - 3))

We now simplify to get:

(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)

4 0
3 years ago
How old are all of y'all if I'm 10 and if you are 12 then what is 12times10
Serjik [45]
12 times ten equals one hundred twenty
3 0
3 years ago
Read 2 more answers
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