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Gennadij [26K]
2 years ago
8

May someone help me out with this please

Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0
9/40=4.44444444444444
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A 6-pound watermelon costs $2.40 before a 30% discount. Which equation would allow you to find the discounted price of the water
krok68 [10]

Answer:

Price after discount = 2.4 (1-.3)

Price after discount = 2.4 (.7)

Step-by-step explanation:

We know the cost after the discount.

Price after discount = original price - original price * discount rate

Factoring out the original price

Price after discount = original price (1- discount rate)

We know the discount rate = .3 and the original price is 2.4

Price after discount = 2.4 (1-.3)

Price after discount = 2.4 (.7)

Price after discount = 1.68


4 0
3 years ago
164 is the quotient of g and 320
Aneli [31]

Answer:

g=4480

Step-by-step explanation:

4480 /320 = 164

7 0
3 years ago
In factored form please help
Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

\frac{3x^2-3}{x^2-5x+4} ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

\frac{3x^2-3}{x^2-5x+4} = \frac{3(x-1)(x+1)}{(x-1)(x-4)} ← in factored form

3 0
1 year ago
1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe
alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

b) f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

And f(x)= 0  for other case.

The cumulative distribution function would be given by:

F(x) = 0, x

F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8

F(x) = 1, x\geq 8

3 0
2 years ago
What does "a"equal to?
slamgirl [31]
Distribute on the left side
7.4a+22.2=3.2a+43.2
Subtract 3.2a from both sides
4.2a+22.2=43.2
Subtract 22.2 from both sides
4.2a=21
Divide both sides by 4.2
a=5
5 0
2 years ago
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