3 years ago

A rectangle's length is three times its width, w. Its area is 243 square units. Which equation can be used to find the width of

Mathematics

1 answer:

Monica [59]3 years ago

4 0

Answer:

Step-by-step explanation:

Width = w

Length = 3w

Area = 243 square units

length *width = 243

3w * w = 243

3w² = 243

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I need help please. Thank you! :)

Rudiy27

Answer:

12 for the first one and twelve for the second one

Step-by-step explanation:

i think you can divide for the first one and second one if you divide 240÷20 you will get twelve and if you divide 180÷15 you will get 12

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3 years ago

What's the answer to question 10? I don't understand.

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3 years ago

Consider the vector field f(x,y,z)=(2z+3y)i+(3z+3x)j+(3y+2x)kf(x,y,z)=(2z+3y)i+(3z+3x)j+(3y+2x)k.

natima [27]

$\dfrac{\partial f}{\partial x}=2z+3y\implies f(x,y,z)=2xz+3xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=3x+\dfrac{\partial g}{\partial y}=3z+3x$
$\dfrac{\partial g}{\partial y}=3z\implies g(y,z)=3yz+h(z)$
$\implies f(x,y,z)=3xz+3xy+3yz+h(z)$

$\dfrac{\partial f}{\partial z}=3x+3y+\dfrac{\mathrm dh}{\mathrm dz}=3y+2x$
$\dfrac{\mathrm dh}{\mathrm dz}=-x$

But we assume $h$ is a function of $z$ alone, so there is no solution for $h$ and hence no scalar function $f$ such that $\nabla f=\mathbf f$ .