Question

May I know the values of x and y of the following equation?(5-3i)(x-yi) = 3(x+2yi)+1-2i​

Answer 1

Answer:

  (x, y) = (17/31, 1/31)

Step-by-step explanation:

Simplify the given equation, then equate real parts and equate imaginary parts. This will give you two equations in the two unknowns.

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simplify

  (5 -3i)(x -yi) = 3(x +2yi) +1 -2i

 5x -5yi -3xi +3yi² = 3x +6yi +1 -2i

  (5x -3y) +i(-5y -3x) = (3x +1) +i(6y -2)

equate real, imaginary parts

This resolves to the two equations ...

• 5x -3y = 3x +1
• -5y -3x = 6y -2

solve the system

Putting these equations into general form gives ...

  2x -3y -1 = 0

  3x +11y -2 = 0

Using the "cross multiplication method" to solve these equations, we get ...

  x = ((-3)(-2) -(11)(-1))/(2(11) -3(-3)) = 17/31

  y = ((-1)(3) -(-2)(2))/31 = 1/31

The values of x and y that satisfy this equation are ...

  (x, y) = (17/31, 1/31)

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You can read more about the cross multiplication method here.

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