So basically
D=RT
distance=rate times time

D=233
carlos speed=55
maria speed=50
total time=4.4 hours

so therefor we have to represent
carlos time
maria time
carlos distance
maria dstance

let's say that
remember that whatever carlost drove is 233 minus maria (time and distance)
and since we are solving for maria time and distnace, solve in terms of them
maria time=t
maria distance=d
carlos time=4.4-t
carlos distance=233-d

remember total D=RT
find their seperate equations
carlos
233-d=55(4.4-t)

maria
d=50(t)
use them to solve

233-d=55(4.4-t)
subsitute 50(t) for d
233-50t=55(4.4-t)
add 50t to both sides
233=55(4.4-t)+50t
distribute using distributiver protperty (a(b+c)=ab+ac)
55(4.4-t)=242-55t
233=242-55t+50t
add like terms
233=242-5t
add 5t to both sides
233+5t=242
subtract 233 from both sides
5t=9
divdie both sides by 5
t=1.8
maria drove 1.8 hours

the answer is A

8 0

3 years ago

Please help ill give brainliest pls dont guess

LiRa [457]

When y=2 and y=5

1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15

----nonequivalent-----

2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then

-----equivalent------

and no need to find more

7 0

3 years ago