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2 years ago

Solve for side a. Show your work!!

Mathematics

1 answer:

prisoha [69]2 years ago

4 0

It would 100% be 5.

but my explanation is kind of by look, basically it is one more than the four and one less than the 6 :)

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How much higher is 8% than 6%

aleksklad [387]

Answer:

there is a 0.02 or 2% difference

3 0

3 years ago

Read 2 more answers

I will venmo if someone can please help me

shutvik [7]

Answer: 14.967

Step-by-step explanation:

Use Pythagorean Theorem to find the missing length.

a² + b² = c²

x² + 10² = 18²

x² + 100 = 324 [Subtract 100 from both side]

x²= 224

√x² = √224 [solve the square root from both sides]

x ≈ 14.967

4 0

3 years ago

At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =

Papessa [141]

Answer:

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

y = 2 + 2e^x − 4x

y' = 0 + 2e^x - 4

Therefore,

4 = 2e^x - 4

4 = e^x

x = ln 4 = 1.39

To find the y coordinate

y = 2 + 2e^x − 4x

y = 2 + 2e^ln 4 − 4 ln 4

y = 4.45

Hence, they are parallel at point (1.39 and 4.45)

3 0

3 years ago

Offering 50 points really need help on homework

astra-53 [7]

i cant see the photo, it is black, and i cant see it can u post another one,

then i will help (:

4 0

2 years ago

Write an equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the l

mamaluj [8]

The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is $y = \frac{3}{4}x - \frac{5}{4}$

Solution:

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5

Given line is perpendicular to − 4 x − 3 y = − 5

− 4 x − 3 y = − 5

-3y = 4x - 5

3y = -4x + 5

$y = \frac{-4x}{3} + \frac{5}{3}$

On comparing the above equation with eqn 1, we get,

$m = \frac{-4}{3}$

We know that product of slope of a line and slope of line perpendicular to it is -1

$\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}$

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope $m = \frac{3}{4}$

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

$-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}$

$\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}$

$y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}$

Thus the required equation of line is found

8 0

2 years ago