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baherus [9]
2 years ago
6

Find the coordinates of the image of Z(−3,−1) after the translation (x,y)→(x−2,y−7).

Mathematics
1 answer:
polet [3.4K]2 years ago
8 0
<h3>Answer:  (-5, -8)</h3>

======================================================

Explanation:

We get this point by doing two things.

  • Subtract 2 from the x coordinate, due to the x-2
  • Subtract 7 from the y coordinate, because of the y-7

If we started with x = -3, then x-2 = -3-2 = -5. Also, if we had y = -1 then y-7 = -1-7 = -8

So that's how we end up with Z(-3,-1) moving to Z ' (-5, -8)

You could also show your work like this

(x,y) \to (x-2, y-7)\\\\(-3,-1) \to (-3-2, -1-7)\\\\(-3,-1) \to (-5, -8)\\\\

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I’ve Tried solving this and i just can’t get it , 64 = 4 + 12g
Alika [10]

Answer:

5

Step-by-step explanation:

64 = 4 + 12g

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8 0
3 years ago
A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes
Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i

Which is not correct. The correct steps are shown below.

Using distributive property, we get

4(3-2i)+5i(3-2i)

4(3)+4(-2i)+5i(3)+5i(-2i)

12-8i+15i-10i^2

12+7i-10(-1)       [\because i^2=-1]

12+7i+10

22+7i

Therefore, the correct value of (4+5i)(3-2i) is 22+7i.

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3 years ago
How to find the x ?
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Does that say 4 x 8x + 1 = 2(squared)x?
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