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2 years ago

HELP ME!!! I WILL MARK AS BRAINLY

Mathematics

1 answer:

borishaifa [10]2 years ago

4 0

Answer:

Step-by-step explanation:

We can see from the two marked points the coordinates are: (2, 8) and (4, 16)

That means the rise (vertical change) is 16 - 8 = 8 units. And the run (horizontal change) is (4 - 2) = 2 units.

Therefore slope = rise/run = 8/2 = 4.

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The answer and how to solve it

blondinia [14]

U would simpiphy it to then get the awnser

3 0

3 years ago

$150 as a percentage of $500

saveliy_v [14]

I think the answer is 30

Because I did 150÷500×100

3 0

3 years ago

Read 2 more answers

A 150 cm pendulum swings through an arc which measured 100pi cm. In exact radians, through what angle does it swing?

choli [55]

Answer:

Pendulum will swing by an angle 0.666π

Step-by-step explanation:

We have given arc = $100\pi cm$

And length of the pendulum l = 150 cm

Length of the pendulum will be equal to radius of the pendulum so r = 150 cm

Arc is given by $arc=radius\times angle$

So $100\pi =150\times\times \Theta$

$\Theta =0.666\pi$

So pendulum will swing by an angle 0.666π

5 0

2 years ago

A particular state has elected both a governor and a senator. Let A be the event that a randomly selected voter has a favorable

Elodia [21]

Answer:

Step-by-step explanation:

Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.

Suppose that

P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68

From the above we can find out

P(A) = $1-0.44 = 0.56$

P(B) = $1-0.57 = 0.43$

P(AUB) = 0.68 =

$0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30$

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30

b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates

= P(A)-P(AB)+P(B)-P(AB)

$=0.99-0.30-0.30\\=0.39$

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates

=P(A'UB') = P(AB)'

= $1-0.30\\=0.70$

3 0

3 years ago

A baseball player hit 65 home runs in a season. Of the 65 home runs, 19 went to right field, 23 went to right-center field, 9

olchik [2.2K]

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

8 0

3 years ago