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galben [10]
4 years ago
11

Principal Phillipi used a random sample of 20 student records to determine how far, in miles, students live from the school. The

results are shown below.
3, 4, 5, 3, 4,
5, 6, 5, 4, 3,
2, 3, 4, 5, 6,
4, 8, 4, 3, 2
Mathematics
2 answers:
deff fn [24]4 years ago
4 0

Answer:

4.2 miles

Step-by-step explanation:

djyliett [7]4 years ago
4 0

Answer:

The correct answer is b: 4.2

Step-by-step explanation:

The mean distance is adding them all up then dividing by how many there are, which is 20. When you do the math it is 4.2 (and this is correct on edge)

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fenix001 [56]
8/8
I added them together since they say " Altogether "
5 0
3 years ago
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If 25x2- 49y2 has one factor (5x-7y), then the other factor is…..
elena-s [515]
There's only one 1 factor and there are no like terms
6 0
3 years ago
In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅
siniylev [52]

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

iv) Diagonals must bisect each other.

v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.


7 0
4 years ago
Read 2 more answers
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
Need help answering this question
Rasek [7]

Answer:

Step-by-step explanation:

Step 1

we know that sinθ = opp/hyp

so

let x = hyp

sin(23.64) = 5.42/x

0.40=5.42/x

x0.40 = 5.42

x = 13.55

Thefore the length of the hypothenuse is 13.55 Send Love:333

5 0
3 years ago
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