13/15 of her allowance was spent in total.
To solve this, you'd need to find the least common denominator (LCD) so that both fractions have the same number on the bottom. In this case, the first number that you could get with 5 and 3 was 15.
Next, you'd have to multiply the numerator by the same amount as the denominator, so that the fractions are proportionate. So, for 1/5, since we had to multiply 5 by 3 to get 15, we'd multiply 1 by 3 as well, giving us 3/15. Doing the same with 2/3, we'd get 10/15.
Then, you add the two fractions together (10/15 + 3/15 = 13/15).
Now, in any other case, you could probably simplify the fraction after you've solved the problem. If we got 12/15 instead of 13/15, then we could simplify that to 4/5, since both 12 and 15 are divisible by 3. But in this case, this is the simplest form of that fraction.
Hope this helped!!!
Answer:
insta
Step-by-step explanation:
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The practice will end at exactly 4:00 .
Answer:
The linear equation is;
Y = 450 - 2·X
Please find the included graph
Step-by-step explanation:
Whereby we have the following relation;
The cost of 1 pizza = X
The cost of 1 burger = Y
Hence;
450 = Y + 2·X
Which gives;
Y = 450 - 2·X
The linear equation for the situation is therefore as presented above
The graph of the linear equation can be plotted using the assumed data as follows;
Y, X
1, 448
2, 446
3, 444
4, 442
5, 440
6, 438
7, 436
8, 434
9, 432
10, 430
11, 428
12, 426
13, 424
14, 422
15, 420
16, 418
Consider such events:
A - slip with number 3 is chosen;
B - the sum of numbers is 4.
You have to count 
Use formula for conditional probability:
1. The event 
consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
2. The event 
consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
3. Then
Answer: 
