Answer:
10 pounds. Hope this helps!!!!
Step-by-step explanation:
If 2 pound serves 8 people you can express that as a ratio of 2:8 so to get 8 people to 40 you multiply by 5 so you must do the same for the amount of pasta so 2 multiplied 5 equals 10.
Answer:
a. 215.6 in^3
b. 1.51 lb
Step-by-step explanation:
The area of each hand grip hole is that of a circle of radius 0.6 in together with a rectangle 2 in long and 1.2 in wide. So, that area is ...
π·(0.6 in)^2 + (2 in)(1.2 in) = (0.36π +2.4) in^2
The area of the kickboard before the hand grip holes are put in is that of a semicircle of radius 5.5 in together with a rectangle 12 in long and 11 in wide. So, that area is ...
(1/2)·π·(5.5 in)^2 + (12 in)(11 in) = (15.125π +132) in^2
Taking the hand grip holes out, the top area of the board is ...
((15.125π +132) -2(0.36π +2.4)) in^2
= (14.405π + 127.2) in^2
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a. The volume is the product of the area and the thickness, so is ...
((14.405π +127.2) in^2)·(1.25 in) ≈ 215.568 in^3
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b. The weight of the kickboard is the product of its volume and its density:
(215.568 in^3)(0.007 lb/in^3) ≈ 1.509 lb
Answer:
45°
Step-by-step explanation:
Ok, so, there is one thing I need to point out. 45° is the 'main' value if you assume 0°<A<180°. However, sin, cos, and tan have different periods which means that there are infinite values of A where tanA = 1. The general notation that you could put is A = 45° + (n*180°) where n is just a number. For example, if n = 1, you would get an angle of 225°. If you plug tan225° into the calculator, you get 1. If you did radians, you could write A = 
. But ignore that if you haven't. Basically, the answer would be 45° if you are assuming A is between 0° and 180°. Also, you could have just used your calculator and types inverse tan function (
) and plug in 1 to find the primary answer of 45.
Answer: D
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
