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2 years ago

9

Which equation is represented by the table of values below

1 answer:

algol132 years ago

6 0

Answer:

Y= –4X+3

Step-by-step explanation:

Aight, check this out. the X and Ys are gonna form a linear equation.

Y=aX+b

3=a(0)+b===> b=3, so there you got for b

–1=a(1)+3===> a= –4

and the final touch

Y= –4X+3

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(y+3):(y+5)=k:1<br><br> show that y=(5k-3)/(1-k)<br><br> hence y=(5k-2)/(1-k)

luda_lava [24]

hi,

Express the ratios in fractional form, that is

= ( cross- multiply )

y + 3 = k(y + 5) ← distribute

y + 3 = ky + 5k ( subtract ky from both sides )

y - ky + 3 = 5k ( subtract 3 from both sides )

y - ky = 5k - 3 ← factor out y from each term on the left side

y(1 - k) = 5k - 3 ← divide both sides by (1 - k)

y = 5k- 3

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1 - k

4 0

2 years ago

Suppose M is the midpoint of line FG.

alukav5142 [94]

$A)\\|FM|=5y+13;\ |MG|=5-3y\\\\|FG|=|FM|+|MG|\\\\|FG|=(5y+13)+(5-3y)=2y+18\\\\B)\\|FM|=8a+1;\ |FG|=42\\\\|FG|=2|FM|\\\\2(8a+1)=42\\16a+2=42\ \ \ \ \ |subtract\ 2\ from\ both\ sides\\16=40\ \ \ \ \ |divide\ both\ sides\ by\ 16\\a=\frac{40}{16}\\a=\frac{5}{2}\\a=2.5$

6 0

2 years ago

1. Use a property of exponents to write (3b)⁵ as a product of powers. 2. What is the width of the rectangle written as an expone

motikmotik

Answer:

Step-by-step explanation:

1. (3b)^5

= (3b)^2 * (3b)^3.

2. Width = area / length

= 10^4 / 10^3

= 10^(4-3)

= 10 m.

8 0

3 years ago

Rewrite the equations using a negative exponent!! ill give brainliest, any random or incomplete answers will be reported!!

vesna_86 [32]

Answer:

11. $x^{-2}$

12. $m^{-3}$

13. $(x+2y)^{-4}$

14. $(x+3y)^{-2}$

15. $(x+y)^{-3}$

16. $(2x+3y)^{-6}$

17. $(-3m-9)^{-3}$

18. $x^{-4}$

Step-by-step explanation:

In all of them you just subtract the bottom exponent from the top exponent.

5 0

2 years ago

Read 2 more answers

Prove that the following four points will form a rectangle when connected in order

Lemur [1.5K]

Answer:

Step-by-step explanation:

If the diagonals of the rectangle are congruent,

AC = BD

By using formula to calculate the distance between two points,

Distance between two points = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(0, -3) and C(2, 8),

AC = $\sqrt{(8+3)^2+(2-0)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Similarly, distance between two points B(-4, 0) and D(6, 5),

BD = $\sqrt{(5-0)^2+(6+4)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Therefore, both the diagonals are congruent.

Hence, given quadrilateral ABCD is a rectangle.

8 0

3 years ago