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2 years ago

8

How do I do this? I don't get it

2 answers:

Delvig [45]2 years ago

6 0

First: work out the difference (increase<span>) between the two numbers you are comparing. Then: divide the </span>increase<span> by the original number and multiply the answer by 100. If your answer is a negative number then this is a </span>percentage<span> decrease.</span>

mash [69]2 years ago

3 0

Think of this as a fraction. Lets think the fraction is based off of the number "4" 4,8,12,16 Makes the fraction 1\4 (because there's 4 numbers total) then lets add the extra 2 numbers of 4+4.....4,8,12,16,20 ,24 . that makes 1\6. so now all you do is convert the fraction into a percentage.

The Correct Answer Is ----> 50%

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3 years ago

What is 79 881/1000 as decimal

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3 years ago

Write four numbers that round to 700,000 when rounded to the nearest hundred thousand

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699,548
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3 years ago

Read 2 more answers

I NEED HELP ASAP!!!!!

zavuch27 [327]

√y

Step-by-step explanation:

The question given is;

$\frac{y^{\frac{3}{4} } }{y^{\frac{1}{2} } }$

This can be written as;

$y^{\frac{3}{4} } /y^{\frac{1}{2} }$

Apply law indices where you divide same base, subtract the powers

$y^{\frac{3}{4} -\frac{1}{2} } \\\\\\y^{\frac{1}{2} } \\\\\\\sqrt{y}$

Learn More

Indices: brainly.com/question/12685658

Keyword : rational exponents,radical expressions,integer

#learnwithbrainly

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3 years ago

The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th

Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ) of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

$\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19$

Then the probability is given as

$\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162$

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

To know more about Probability

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2 years ago